Tuesday
September 16, 2014

Homework Help: Chemistry

Posted by Kevin on Tuesday, October 25, 2011 at 12:38am.

Calculate the pH of a 100mL solution of 0.10M acetic acid ka=1.8x10(-5)

i calculated the pH to be 2.87

from the square root of
(1.8x10(-5) * 0.1, the negative log gives me the pH.

The next question wants you to calculate the pH with 50mL HCl added. I found the pH to be 2.78 by just adding .05 to the bottom [HA] value are these correct so far?

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