Posted by Karishma on .
The radius of a right circular cylinder is given by t + 9
and its height is (1/9)*(t^0.5)
where t is time in seconds and the dimensions are in inches. Find the rate of change of the volume with respect to time.
units = in^3/s

CALCULUS help please 
Reiny,
volume of cylinder = πr^2 h
= π(1/9)t^.5)(t+9)
= (π/9)t^1.5 + πt
dV/dt = (π/6)t + π