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November 22, 2014

November 22, 2014

Posted by **Karishma** on Monday, October 24, 2011 at 10:37pm.

and its height is (1/9)*(t^0.5)

where t is time in seconds and the dimensions are in inches. Find the rate of change of the volume with respect to time.

units = in^3/s

- CALCULUS help please -
**Reiny**, Monday, October 24, 2011 at 10:46pmvolume of cylinder = πr^2 h

= π(1/9)t^.5)(t+9)

= (π/9)t^1.5 + πt

dV/dt = (π/6)t + π

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