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January 28, 2015

January 28, 2015

Posted by **Farrah** on Monday, October 24, 2011 at 10:08pm.

Determine the values of k for which the function f(x)=4x^2-3x+2kx+1 have 2 zeros

- Math -
**Reiny**, Monday, October 24, 2011 at 10:39pmif b^2 - 4ac < 0 ---> no real zeros

if b^2 - 4ac = 0 ---> one real zero

ifb^2 - 4ac > 0 ---> two real zeros

if will do the 2nd question.

a=4, b= 2k-3 , c = 1

b^2 - 4ac

= (2k-3)^2 - 4(4)(1)

= 4k^2 - 12k + 9 - 16

= 4k^2 - 12k - 7

= (k + 1)(4k - 7)

(k+1)(4k-7) > 0 for 2 real roots

k < -1 OR k > 7/4

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