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Posted by **tracy** on Monday, October 24, 2011 at 9:42pm.

the square root of 6m minus 5 = m

A. {1}

B. {5}

C. {1, 5}

D. no real solution

I think its B

- algebra,math -
**Reiny**, Monday, October 24, 2011 at 10:22pm√(6m) - 5 = m

√(6m) = m+5

square both sides

6m = m^2 + 10m + 25

m^2 + 4m + 25 = 0

m = (-4 √-84)/2

no real solution

if you think it is B), why not check it

LS = √30 - 5

RS = 5

mmmhhh

**However**, if you meant:

√(6m-5) = 5

then 6m-5 = 25

6m = 30

m = 5

See what happens if you don't use brackets to avoid ambiguity?

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