A block is pushed across a horizontal surface with a coefficient of kinetic friction of 0.15 by applying a 150 N horizontal force. If the block accelerates at the rate of 2.53 m/s2 (squared), what is the mass of the block?

ur face

38N

To find the mass of the block, we can use Newton's second law of motion, which states that the force (F) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a).

In this case, we know the force applied horizontally (F) is 150 N, and the acceleration (a) is 2.53 m/s^2. We need to find the mass (m) of the block.

The formula for Newton's second law is:

F = m * a

Rearranging the formula to solve for mass (m), we have:

m = F / a

Substituting the given values:

m = 150 N / 2.53 m/s^2

m ≈ 59.29 kg

Therefore, the mass of the block is approximately 59.29 kg.