Posted by **Anonymous** on Monday, October 24, 2011 at 9:14pm.

Show all work.

A projectile is fired from a cliff 100 ft above the water at an inclination of 45 degrees to the horizontal, with a muzzle velocity of 260 ft/second. The height of the projectile above the water is given by h(x)= ((-32x^2)/(260)^2)+x+100, where x is the horizontal distance of the projectile from the base of the cliff. How far from the base of the cliff is the height of the projectile a maximum?

## Answer This Question

## Related Questions

- pre-calc - analyzing the motion of a projectile: a projectile is fired from a ...
- physics - a projectile with a muzzle velocity of 550 m/s is fired from the a gun...
- math - A projectile is fired directly upward with a muzzle velocity of 860 feet ...
- Algebra - A projectile is fired straight up in the air. Let h(t) be its height ...
- Physics 124 - A projectile is fired from the top of a cliff at 14.2 m/s at an ...
- science - A projectile is fired with an initial speed of 120m.s' at an angle of ...
- science - A projectile is fired with an initial speed of 120m.s' at an angle of ...
- physics - A cannon on a level plain is aimed 50 degrees above th e horizontal ...
- Physics - A projectile is fired straight up from a cliff which is 200 feet above...
- Math - A projectile is fired straight up from a cliff which is 200 feet above ...

More Related Questions