Thursday

August 28, 2014

August 28, 2014

Posted by **Anonymous** on Monday, October 24, 2011 at 9:14pm.

A projectile is fired from a cliff 100 ft above the water at an inclination of 45 degrees to the horizontal, with a muzzle velocity of 260 ft/second. The height of the projectile above the water is given by h(x)= ((-32x^2)/(260)^2)+x+100, where x is the horizontal distance of the projectile from the base of the cliff. How far from the base of the cliff is the height of the projectile a maximum?

- College Algebra -
**Reiny**, Monday, October 24, 2011 at 10:04pmThe way you typed it, the equation reduces to

h(x) = (-2/4225)x^2 + x + 100

h'(x) = (-4/4225)x + 1 = 0 for a max height

-4x = -4225

x = 1056.25 ft from base of cliff

evaluate h(1056.25) to get the actual max height.

**Related Questions**

pre-calc - analyzing the motion of a projectile: a projectile is fired from a ...

physics - a projectile with a muzzle velocity of 550 m/s is fired from the a gun...

Physics 124 - A projectile is fired from the top of a cliff at 14.2 m/s at an ...

physics - A cannon on a level plain is aimed 50 degrees above th e horizontal ...

physics - A projectile is fired at an angle of 30ᵒ above the horizontal ...

Physics - A projectile is fired straight up from a cliff which is 200 feet above...

Math - A projectile is fired straight up from a cliff which is 200 feet above ...

physics - A projectile is fired with an initial velocity of 24 m/s at 40 degrees...

physics - A projectile is fired into the air from the top of a cliff of height h...

physics - A projectile is shot from the edge of a cliff 125 m above ground level...