Posted by **Ghiffari** on Monday, October 24, 2011 at 8:34pm.

The numerator of a fraction is two less than its denominator. When both numerator and denominator are increased by 3, the fraction is incre

ased by 3/20. Find the original fraction. Pls include solution and workings thx :)

- Math -
**Reiny**, Monday, October 24, 2011 at 9:20pm
first denominator -- x

first numerator ---- x-2

new denominator -- x+3

new numerator ---- x+1

(x-2)/x + 3/20 = (x+1)/(x+3)

times 20x(x+3) , the LCD

20(x+3)(x+1) + 3x(x+3) = 20x(x+1)

expanding and simplifying gave me

x^2 + 3x - 40 = 0

(x-5)(x+8) = 0

x = 5 or x=-8

if x=5, the original fraction was 3/5

if x=-8 the original fraction was -10/-8 or 5/4

check for 3/5 , new fraction would be 6/8 or 3/4

3/5 + 3/20 = 12/20 + 3/20 = 15/20 = 3/4

but for 5/4, new fraction would be 8/7

5/4 + 3/20 = 28/20 = 7/5 ≠ 8/7

BUT, if we take the unsimplified fraction -10/-8 , new fraction would be -7/-5 = 7/5

So the original fraction would be 3/5 for sure, but

also the unsimplified fraction -10/-8

- Math -
**Shamaiel intkhab**, Saturday, December 17, 2016 at 12:46pm
Let denominator and numerator be x

The numerator is 2 less than its denominator so

X-2/x

It will increased by 3 and will become 3/20 so

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