Using the data collected for part b on your data sheet, calculate the molar mass of the unknown acid. Include the calculation for each trial and the average.
Trial One Results:
Mass unknown acid: 0.500g
Final buret reading: 18.01mL
Initial buret reading: 0.11mL
Volume NaOh used: 17.90mL
1. moles NaOH = M x L
2. moles NaOH = moles unknown acid.
3. moles unknown = grams unk/molar mass unknown
Solve for molar mass unknown. Volums are final readings minus initial readings.
To calculate the molar mass of the unknown acid, we need to use the equation:
Molar mass (g/mol) = (Mass of unknown acid (g) / Volume of NaOH used (L)) * (1 L / 1000 mL) * (1 mol NaOH / 1 mol unknown acid)
Here are the calculations for Trial One:
Step 1: Convert the volume of NaOH used from mL to L:
Volume of NaOH used = 17.90 mL * (1 L / 1000 mL) = 0.01790 L
Step 2: Calculate the number of moles of NaOH used:
Moles of NaOH = Volume of NaOH used (L) * Molarity of NaOH (mol/L)
Assuming we know the molarity of NaOH, we can use that value to calculate the moles of NaOH.
Step 3: Use the balanced chemical equation to determine the ratio between NaOH and the unknown acid.
Assuming we know the balanced chemical equation, we can determine the ratio between NaOH and the unknown acid. For example, if the equation is: NaOH + HX → NaX + H2O, the ratio is 1:1.
Step 4: Calculate the moles of unknown acid:
Moles of unknown acid = Moles of NaOH
Step 5: Calculate the molar mass of the unknown acid:
Molar mass (g/mol) = Mass of unknown acid (g) / Moles of unknown acid
Repeat these calculations for each trial, then find the average molar mass by calculating the mean of the individual trial molar masses.
To calculate the molar mass of the unknown acid, you need to use the concept of stoichiometry and the equation for the reaction between the acid and sodium hydroxide (NaOH). The balanced equation for this reaction is:
Acid (HA) + NaOH -> NaA + H2O
Here, HA represents the unknown acid and NaA represents the sodium salt of the acid.
To calculate the molar mass, you need to determine the number of moles of NaOH used in the reaction.
Step 1: Calculate the volume of NaOH used in liters:
Volume NaOH used = Final buret reading - Initial buret reading
= 17.90 mL - 0.11 mL
= 17.79 mL or 0.01779 L
Step 2: Calculate the number of moles of NaOH:
Number of moles NaOH = Volume NaOH used (in liters) * Molarity of NaOH
Assuming the molarity of NaOH is given, you can substitute the values into the equation.
Step 3: Calculate the number of moles of HA (unknown acid):
From the balanced equation, it can be seen that the stoichiometric ratio between NaOH and HA is 1:1. This means that for every mole of NaOH used, there is one mole of HA.
Number of moles HA = Number of moles NaOH
Step 4: Calculate the molar mass of HA:
Molar mass HA = Mass of HA / Number of moles HA
Substituting the given values:
Mass of HA = 0.500 g
Number of moles HA = Number of moles NaOH (calculated in Step 2)
Calculate the molar mass for all trials and find the average:
Trial One:
Molar mass HA (Trial One) = 0.500 g / Number of moles HA (Trial One)
Repeat the same calculation for any other trials you have, and then calculate the average molar mass by taking the average of all the trials.
u kno im just letting u know
THIS IS NOT A NOT 2 DO HW FOR KIDS SITE !!!
btw - srry about what i said before i didn't know that u hav this separate u could of wrotw CHEMISTRY PLEASE HELP part 1 then part 2 and 3