Sunday

August 31, 2014

August 31, 2014

Posted by **terra** on Monday, October 24, 2011 at 7:34pm.

has a root in [0.5, 0.6]. Apply the Bisection Method twice to find an interval of length 0.025 containing this root.

I have NO idea where to go with that equals 0 part...I could figure it without it but that throws me off completely..you can't plug any numbers in

- calculus -
**Steve**, Monday, October 24, 2011 at 11:57pmIf there is a root in [0.5,0.6] then that means that f(.5) * f(.6) < 0

That is, the graph crosses the axis there somewhere, and the function changes sign.

f(.5) = -0.9374

f(.6) = 0.2062

So, bisect the interval

f(.55) = -0.3539

Still negative, so bisect again

f(.575) = -0.0708

Still negative, so the root is in [0.575,0.6]

In fact, it turns out to be 0.5813

**Related Questions**

Trig. - sec^2xcotx-cotx=tanx (1/cos)^2 times (1/tan)-(1/tan)=tan (1/cos^2) times...

Trig - 4tan^2u-1=tan^2u 3tan^2u=1 tan^2u=1/3 sq. root of (tan^2u)=sq. root of (1...

trig - Given that tan 45=1, use tan(x+y) to show that tan 22.5= /2 - 1. (/is ...

Trigonometry - Find the exact value of tan(a-b) sin a = 4/5, -3pi/2<a<-pi...

PreCalculus - Hi I need some assistance on this problem find the exact value do ...

math - Use the exact values of the sin, cos and tan of pi/3 and pi/6, and the ...

Math-Trigonometry - Show that if A, B, and C are the angles of an acute triangle...

calculus - can anyone tell me if tan-1x= 1 over tan x? No. They are different. ...

Calc - y= cube root (1+tan(t)) OR y= (1+tan(t))^(1/3) The answer I got was y'= (...

mathematics - 1.)Sin^-1(x)+Sin^-1(y)+Sin^-1(z)= pie Prove that X.root(1-y^2)+y....