physics
posted by anonymous on .
A long jumper leaves the ground at an angle of 25.2 to the horizontal and at a speed of
11.2 m/s.
How far does he jump? The acceleration
due to gravity is 9.8 m/s2 .
Answer in m
What maximum height does he reach?
Answer in units of m

1. Dh = Vo^2*sin(2A) / g,
Dh = (11.2)^2*sin50.4 / 9.8 = 9.86m.
2. Yo = ver. = 11.2sin25.2 = 4.77m/s.
h = (Yf^2  Yo^2) / 19.6,
h = (0  (4.77)^2) / 19.6 = 1.161m