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November 25, 2014

November 25, 2014

Posted by **JessieLynne** on Monday, October 24, 2011 at 2:06pm.

x^2 + y^2 - 6x+8y+9=0

- Algebra -
**Steve**, Monday, October 24, 2011 at 3:15pmThat is the standard general form. Now, if you want it as a conic section in standard form, group the x and y terms:

(x^2 - 6x) + (y^2 + 8y) + 9 = 0

Now, make each parenthesized group a perfect square, then subtract off whatever you had to add in:

(x^2 - 6x + 9) + (y^2 + 8y + 16) + 9-9-16 = 0

(x-3)^2 + (y-4)^2 = 16

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