Sunday

April 20, 2014

April 20, 2014

Posted by **johnathon** on Monday, October 24, 2011 at 11:42am.

- calculus -
**Steve**, Monday, October 24, 2011 at 12:11pmFind where the graphs intersect. That will give you the limits of integration.

4x^2 = 7x^2 at x=0

4x^2 = 3-4x at x = 0.5

7x^2 = 3-4x at .43

4x^2 < 7x^2, so we need to integrate

7x^2 - 4x^2 from 0 to 0.43

3-4x - 4x^2 from 0.43 to 0.5

Int(3x^2) = x^3 [0,0.43] = 0.08

Int(3-4x-4x^2) = 3x - 2x^2 - 4/3 x^3 [0.43,0.5) = 0.02

So, the total area = 0.10

If my math is right . . .

- calculus -
**johnathon**, Monday, October 24, 2011 at 1:52pmthanks

the exact answer is 29/294

- calculus -
**Anonymous**, Sunday, September 9, 2012 at 8:41pmf(X)3x^2 + 7x-20 G(x)= x+4 FIND f/g

**Related Questions**

Calculus-Area between curves - Sketch the region enclosed by the given curves. ...

Calculus (Area Between Curves) - Find the area of the region bounded by the ...

Calculus Area between curves - Sketch the region enclosed by the given curves. ...

calculus - consider the area enclosed between the curves f(x)=x^2 and g(x)=4x ...

calculus - consider the area enclosed between the curves f (x) = x2 and g (x) = ...

Calculus (Area Between Curves) - Find the area of the region IN THE FIRST ...

CALCULUS ONE! - The graph of sinx and cosx intersect once between 0 and pi/2. ...

calculus - Find the angle of intersection between the curves f(x) = 2x + 3 and g...

Calculus - 1. Find the area of the region between the curves y=sin(x pi/2) and y...

Calculus - 1. Find the area of the region between the curves y=sin(x pi/2) and y...