Calculate the mass of Glauber's salt needed to lower the temp of air in a room by 6.3 C. The mass of air in the room is 555.4 kg, the specific heat is 1.2J/g-c

The heat needed to change T by 6.3 C is

q = 555400g x 1.2 J/g*c x 6.3

You will need to know the heat information for Na2SO4.10H2O to do the remaining part of the problem.

To calculate the mass of Glauber's salt needed, we can use the equation:

Q = mcΔT

Where:
Q is the heat absorbed or released by the substance (in this case, Glauber's salt),
m is the mass of the substance,
c is the specific heat,
ΔT is the change in temperature.

First, let's convert the specific heat from J/g-C to J/kg-C:

1 g = 0.001 kg
1 g-C = 0.001 kg-C

Therefore, the specific heat of air in kg-C will be:
1.2 J/g-C * 0.001 kg/g = 0.0012 J/kg-C

Now we can calculate the heat absorbed or released by the air in the room using the equation:

Q = mcΔT

Q = (555.4 kg) * (0.0012 J/kg-C) * (-6.3 C)

Since we want to lower the temperature of the air in the room, the change in temperature will be negative.

Q = - 41.8642 J

Now we can calculate the mass of Glauber's salt needed to absorb this amount of heat.

Q = mcΔT

- 41.8642 J = m(390 J/g) * (1.2 J/g-C)

To calculate the mass, we can rearrange the equation:

m = - 41.8642 J / (390 J/g * 1.2 J/g-C)

m = - 0.090189 g

The negative sign indicates that Glauber's salt is releasing heat (exothermic process) to lower the temperature of the air in the room.

Therefore, the mass of Glauber's salt needed to lower the temperature of the air in the room by 6.3 C is approximately 0.090189 grams.