Posted by Bernardo on .
A street light is at the top of a 18 ft tall pole. A woman 6 ft tall walks away from the pole with a speed of 6 ft/sec along a straight path. How fast is the tip of her shadow moving when she is 45 ft from the base of the pole?

calc related rates 
Steve,
Draw a triangle.
If the woman is x feet from the pole, and her shadow extends an additional y feet,
18/(x+y) = 6/y
18y = 6(x+y)
18x = 6x + 6y
12x = 6y
2x = y
2 dx/dt = dy/dt
2(6) = dy/dt
Now, the distance of the shadow tip from the pole is x+y, so its speed is dx/dt + dy/dt = 6+12 = 18 ft/sec, regardless of the distance.