Posted by unknown on Monday, October 24, 2011 at 9:52am.
Suppose there were p plates. If you count both the ships and the cracks, then you count chipped&cracked twice.
p - 2p/3 - p/2 + p/4 = 2
12p - 8p - 6p + 3p = 24
p = 24
So, 16 were chipped
12 were cracked
6 both
2 undamaged
36
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