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Posted by on Monday, October 24, 2011 at 9:14am.

two cars leave the same point at noon. one car travels north and the other car travels east. suppose the northbound car is traveling 40mph, and after two hours, the two car are 100 miles fast is the other car going?

  • math - , Monday, October 24, 2011 at 10:05am

    recall that speed is distance travelled over time.
    let x = speed of the other car.
    then we set-up the equation.
    when you draw the directions they're travelling, you will form a right triangle. thus recall that in a right triangle, the hypotenuse (in this the the distance between them which is 100 miles) is given by the Pythagorean theorem:
    c^2 = a^2 + b^2
    we equate distances:
    100^2 = (40*2)^2 + (2x)^2
    10000 = 80^2 + 4x^2
    10000 - 6400 = 4x^2
    3600 = 4x^2
    x^2 = 900
    x = 30 mph

    hope this helps~ :)

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