Friday

April 17, 2015

April 17, 2015

Posted by **Erica** on Monday, October 24, 2011 at 3:24am.

I started working the problem out, and so far I got the lim as z→-∞ of [arctan (-1) - arctan (z)].

I'm a little bit confused exactly what is means when you plug -∞ into z, and how to solve the problem from here.

Thank you!

- Calc -
**drwls**, Monday, October 24, 2011 at 5:30amThe indefinite integral is arctan x, as you have already indicated.

arctan(-infinity), the angle that has a tangent of -infinity, is (3/2)*pi

arctan(-1) = (7/8)*(2 pi) = (7/4)pi

That makes the answer pi/4

**Answer this Question**

**Related Questions**

L'Hopitals Rule - 5) Use the L’Hopital’s method to evaluate the following limits...

calc - also: integral of tan^(-1)y dy how is integration of parts used in that? ...

maths - A sequence is defined by un = 2×(−0.5)n + 3 (n = 1,2,3, . . .). ...

maths - A sequence is defined by un = 2×(−0.5)n + 3 (n = 1,2,3, . . .). ...

calc 3 - Find the limit ( e^-3t i + tsin(1/t)j + arctan tk ) if it exists. If ...

Calculus - Find the indicated limits. If the limit does not exist, so state, or ...

Calculus - Find the indicated limits. If the limit does not exist, so state, or ...

calculus - Let f be a function defined by f(x)= arctan x/2 + arctan x. the value...

Math - Arrange these in order from least to greatest: arctan(-sqrt3), arctan 0, ...

Calculus - Note that pi lim arctan(x ) = ---- x -> +oo 2 Now evaluate / pi \ ...