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November 28, 2014

November 28, 2014

Posted by **Tim** on Sunday, October 23, 2011 at 11:56pm.

- Calculus -
**Steve**, Monday, October 24, 2011 at 10:41amLet the lighthouse be h miles from shore. Let x be the distance of the ship from a point on shore closest to the lighthouse.

h/(x+5) = tan 12°

h/x = tan 22°

so, equating h,

(x+5)tan 12° = x tan 22°

.212(x+5) = .404x

1.06 = .282x

x = 3.759 mi

Now, the distance of the ship from the lighthouse, d, can be found by

3.759/d = cos 22°

d = 4.05 mi

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