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October 23, 2014

October 23, 2014

Posted by **Natasha** on Sunday, October 23, 2011 at 11:40pm.

- algebra -
**Steve**, Monday, October 24, 2011 at 10:32amConsider t=0 when train A passes the station. After that, at some time t, the trains will be at the same distance. B travels 0.5 hour less than A.

88(t-.5) = 80t

88t - 44 = 80t

8t = 44

t = 5.5

So, 5.5 hours after 5:10, the trains will have gone the same distance (440 miles) from the station.

That is, at 10:40, B passes A.

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