Posted by **Kestrel** on Sunday, October 23, 2011 at 10:19pm.

a rectangular field with an area of 8000 m^2 is enclosed by 400 m of fencing , detemine the dimesions of the field to the nearest tenth of a metre

- Math -
**Jai**, Sunday, October 23, 2011 at 10:38pm
first we represent the unknowns using variables:

let x = length

let y = width

recall that perimeter of rectangle is just,

P = 2x + 2y

since P is given (which is 400), we can get an expression of width in terms of length:

400 = 2x + 2y

400 - 2x = 2y

y = 200 - x

then to get the dimensions, we use the area given. recall that area of rectangle is just,

A = xy

substituting,

8000 = x(200 - x)

8000 = 200x - x^2

x^2 - 200x + 8000 = 0

then solve for x using quadratic equation. then also solve for y.

hope this helps~ :)

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