Sunday

December 21, 2014

December 21, 2014

Posted by **Kestrel** on Sunday, October 23, 2011 at 10:19pm.

- Math -
**Jai**, Sunday, October 23, 2011 at 10:38pmfirst we represent the unknowns using variables:

let x = length

let y = width

recall that perimeter of rectangle is just,

P = 2x + 2y

since P is given (which is 400), we can get an expression of width in terms of length:

400 = 2x + 2y

400 - 2x = 2y

y = 200 - x

then to get the dimensions, we use the area given. recall that area of rectangle is just,

A = xy

substituting,

8000 = x(200 - x)

8000 = 200x - x^2

x^2 - 200x + 8000 = 0

then solve for x using quadratic equation. then also solve for y.

hope this helps~ :)

**Answer this Question**

**Related Questions**

Grade 11 Functions - A rectanguler field with an area of 8000 meters squared is ...

math - a rectangular field is to be enclosed with 600m of fencing. Find the ...

MATH - A rectangular field is to be enclosed with 1200 ft of fencing. If the ...

Math 156 - A rectangular field is to be enclosed with 1200 ft. of fencing. If ...

Math - A rectangular field is to be enclosed with 1270 ft of fencing. If the ...

math - A rectangular field is to be enclosed with 1130 ft of fencing. If the ...

calculus - 1.Ruth has 240 feet of fencing available to enclose a rectangular ...

algebra - A man has 400 meters of fencing and wants to fence in a rectangular ...

precalculus - A rectangular field is to be enclosed by a fence and divided into...

math - determine the maximum area of a rectangular field that can be enclosed by...