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College Algebra

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y varies directly as the third power x and inversely as Z. If y=16 when x=4 and z=8,find y when x=9 and z=6

  • College Algebra - ,

    y = (kx^3)/z
    substituting the given values to find the constant k,
    16 = k(4^3)/8
    16 = k(64)/8
    16 = 8k
    k = 2
    therefore,
    y = (2x^3)/z
    if x = 9 and z = 6,
    y = 2*(9^3)/6
    y = 243

    hope this helps~ :)

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