An egg is thrown horizontally off the roof of SI, which is 60 meters high, with an initial velocity of 6.5 m/s. How long does it take to hit the ground? How far does it go in the x direction?
8.7s,56.55m
@ K,
You should check your work before posting an answer. The correct answer should be a) 3.5s b) 21m
A 3.5S
To find the time it takes for the egg to hit the ground, we can use the equation of motion:
h = (1/2) * g * t^2
where h is the initial height of the egg (60 meters), g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time taken.
Rearranging the equation to solve for t, we have:
t = sqrt(2h/g)
Substituting the values, we get:
t = sqrt(2 * 60 / 9.8)
t ≈ 3.19 seconds
Therefore, it takes approximately 3.19 seconds for the egg to hit the ground.
To find the horizontal distance the egg travels (x-direction), we can use the equation:
distance = initial velocity * time
Given that the initial velocity of the egg is 6.5 m/s and the time it takes to hit the ground is approximately 3.19 seconds, we can calculate the distance traveled:
distance = 6.5 m/s * 3.19 s ≈ 20.735 meters
Therefore, the egg travels approximately 20.735 meters in the x-direction.
The horizontal initial velocity does not affect the time to hit the ground.
You should know how to compute how long it takes to fall 60 m, since you are in an "honors" class.
Multiply that time by 6.5 m/s for part 2.