Tuesday

October 21, 2014

October 21, 2014

Posted by **Jc** on Sunday, October 23, 2011 at 8:32pm.

- Physics -
**Kayrie**, Wednesday, March 13, 2013 at 8:13pmUse the rotational energy equation, E = 0.5Iω², where I is the moment of inertia for a long thin rod with an axis through it's midpoint (I = (1/12)mL²).

E = 0.5Iω²

E = 0.5 [1/12)mL²] ω²

E = (1/24) mL² ω²

Find ω by multiplying the rpm by 2π and then dividing by 60 to put units into rad/sec (or multiply ω by π/30)

3450 * 2π = 21 676.9... rad/min

(21 676.9... rad/min)/60 = 361.28... rad/sec

Insert into energy eqn and solve

E = (1/24) mL² (361.28...rad/s)²

E = (1/24)(0.65kg)(0.55m²)(361.28...rad/s)²

E = ~1069 J

**Answer this Question**

**Related Questions**

physics - An 83.2-kg propeller blade measures 2.24m end to end. Model the blade ...

physics - An 83.2-kg propeller blade measures 2.24m end to end. Model the blade ...

Physics - An 83.2-kg propeller blade measures 2.24m end to end. Model the blade ...

Physics - Consider a 52-cm-long lawn mower blade rotating about its center at ...

Physics - Consider a 59-cm-long lawn mower blade rotating about its center at ...

physics - a certain type of propeller blade can be modeled as a thin uniform bar...

physics - The large blade of a helicopter is rotating in a horizontal circle. ...

Physics - The large blade of a helicopter is rotating in a horizontal circle. ...

physics - The large blade of a helicopter is rotating in a horizontal circle. ...

Physics - A certain type of propeller blan can be modeled as a thin uniform bar ...