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January 31, 2015

January 31, 2015

Posted by **rachel** on Sunday, October 23, 2011 at 7:29pm.

directions: find the points of inflection and discuss the concavity of the graph of the function...

1. f(x)=(1/2)x^4+2x^3

2. f(x)=x^3-6x^2+12x

3. f(x)=(1/4)x^4-2x^2

4. f(x)=2sinx+sin2x, [0,2ð)

- calculus -
**Steve**, Monday, October 24, 2011 at 12:36pm1.

f = 1/2 x^4 + 2x^3

f' = 2x^3 + 6x^2

f'' = 6x^2 + 12x

f' = 0 at x=0,0,-3 so the possible mins/maxes are there

f'' = 0 at 0,-2 so the inflection is there.

At x=0, f'=0 and f''=0, so not a min/max -- inflection

At x=-3, y'' > 0, so concave up (min)

Proceed similarly with the others.

rechneronline . de is a good grapher

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