Posted by John on Sunday, October 23, 2011 at 7:08pm.
Assume friction on ice is zero. All the force goes for acceleration.
Minimum possible time t is such that
22 m = (a/2)*t^2 with maximum possible a
Maximum accelaration a is
a = Fmax/m = (12*9.8 N)/30 kg
= 3.92 m/s^2
Now solve for t in the first equation, using that a value.
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