Lithium reacts with nitrogen gas according to the following reaction: 6Li(s)+N2(g)-->2LiN(s)
What mass of lithium (in g ) is required to react completely with 59.9 mL of N2 gas at STP?
chemistry 105 - ALISON, Sunday, October 23, 2011 at 5:30pm
Use the ideal gas law..
and solve for moles of N2
solve for n.
then use "n" moles of N2 and then set up an conversion factor.
___moles of N2 x( 6mol Li/2mol N2) x (MolarMass Li/1mol of Li)
Then that gives you your mass of Lithium required to react.
Hope that helps!
chemistry 105 - Tyler, Thursday, October 9, 2014 at 2:57am