For a chemistry lab the experiment was to carry out an acid-base titration to determine the exact concentration of a sodium hydroxide solution.

Two trials were completed and the data collected was: mass of weighing paper, mass of weighing paper + KHP, mass of KHP, initial buret reading, final buret reading, and volume of NaOH.

The molecular weight of KHP is 204.44 grams/mol.

I need to find the number of moles of KHP, the number of moles of NaOH and the concentration of NaOH but i am not sure how to do this. Please help,thank you!!

moles KHP = grams/molar mass

moles NaOH = moles KHP
M NaOH = moles NaOH/L NaOH

For my first trial KHP was 1.00g and for the second trial it was the same. So to find moles of KHP would I do 204.44g/mol X 1/1g which would be 204.44g/mol?

To find the number of moles of KHP (potassium hydrogen phthalate), you can use the following steps:

1. Calculate the mass of KHP used in each trial by subtracting the mass of the weighing paper from the mass of weighing paper + KHP.

Mass of KHP = Mass of weighing paper + KHP - Mass of weighing paper

2. Convert the mass of KHP to moles by dividing it by the molar mass of KHP.

Moles of KHP = Mass of KHP / Molar mass of KHP

To find the number of moles of NaOH (sodium hydroxide), you need to use the stoichiometric ratio between KHP and NaOH. This ratio can be determined from the balanced chemical equation for their reaction. Assuming the reaction is 1:1, it means that one mole of KHP reacts with one mole of NaOH.

3. Determine the moles of NaOH based on the moles of KHP.

Moles of NaOH = Moles of KHP (since they react in a 1:1 ratio)

Finally, to find the concentration of NaOH, you need to consider the volume of NaOH used in the titration.

4. Calculate the concentration of NaOH by dividing the moles of NaOH by the volume of NaOH used in the titration.

Concentration of NaOH = Moles of NaOH / Volume of NaOH

Note: Make sure to use the appropriate units throughout the calculations to ensure accurate results.