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Posted by on Sunday, October 23, 2011 at 1:06pm.

The second term of a geometric progression is 12 more than the first term given that the common the ratio is half of the first term. Find the third term of the Geometric progression

  • Geometric progression - , Friday, February 17, 2012 at 10:26am

    Solution.Tn=ar'n-1 where n=3

  • Geometric progression - , Thursday, October 11, 2012 at 7:55am

    ar = 12 + a (i)
    ar^2 = x (ii)
    subtract equ (i) from equ (ii)
    a = 6
    substituting a = 6 into equ (i)
    ar = 12 + a
    6r = 12 + 6=18
    r = 3.
    ar'2 = 6 * 3'2
    ar'2 = 54

  • Algebra - , Saturday, July 11, 2015 at 9:50am

    65

  • Geometric progression - , Saturday, July 11, 2015 at 10:01am

    ar'2=54

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