Posted by Anonymous on Sunday, October 23, 2011 at 1:06pm.
The second term of a geometric progression is 12 more than the first term given that the common the ratio is half of the first term. Find the third term of the Geometric progression

Geometric progression  Charles, Friday, February 17, 2012 at 10:26am
Solution.Tn=ar'n1 where n=3

Geometric progression  Babalola Joshua, Thursday, October 11, 2012 at 7:55am
ar = 12 + a (i)
ar^2 = x (ii)
subtract equ (i) from equ (ii)
a = 6
substituting a = 6 into equ (i)
ar = 12 + a
6r = 12 + 6=18
r = 3.
ar'2 = 6 * 3'2
ar'2 = 54 
Algebra  Assatu, Saturday, July 11, 2015 at 9:50am
65

Geometric progression  Assatu, Saturday, July 11, 2015 at 10:01am
ar'2=54