Homework Help: Geometric progression

Posted by Anonymous on Sunday, October 23, 2011 at 1:06pm.

The second term of a geometric progression is 12 more than the first term given that the common the ratio is half of the first term. Find the third term of the Geometric progression

Geometric progression - Charles, Friday, February 17, 2012 at 10:26am
Solution.Tn=ar'n-1 where n=3
Geometric progression - Babalola Joshua, Thursday, October 11, 2012 at 7:55am
ar = 12 + a (i)
ar^2 = x (ii)
subtract equ (i) from equ (ii)
a = 6
substituting a = 6 into equ (i)
ar = 12 + a
6r = 12 + 6=18
r = 3.
ar'2 = 6 * 3'2
ar'2 = 54

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