Posted by **Kestrel** on Sunday, October 23, 2011 at 12:50am.

Determine the values of k for which the function f(x)=4x^2-3x+2kx+1 has 2 zeros

- Math -
**Jai**, Sunday, October 23, 2011 at 2:18am
recall that the formula for discriminant:

D = b^2 - 4ac

if

D < 0 : two imaginary roots

D = 0 : one root

D > 0 : two real roots

thus, given the equation, we can substitute the values of a, b and c in the discriminant, which must be > 0:

(2k - 3)^2 - 4(4)(1) > 0

4k^2 - 12k + 9 - 16 > 0

4k^2 - 12k - 7 > 0

(2k - 7)(2k + 1) > 0

these are the ranges of values:

k > 7/2

k < -1/2

hope this helps~ :)

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