Thursday

July 31, 2014

July 31, 2014

Posted by **Ricky** on Saturday, October 22, 2011 at 11:49pm.

- Adv algebra -
**Jai**, Sunday, October 23, 2011 at 2:20amthere is only one number which satisfies "the square of itself is equal to itself": it is 1. (0 is also the other but it is stated that q cannot be equal to 0)

therefore,

(x-1)(x-1) = x^2 + 2x + 1

p = 2

q = 1

hope this helps~ :)

**Related Questions**

Algebra - The equation x^2+px+q=0, q cannot be equal to 0, has two unequal roots...

Math - The equation x^2+px+q=0, q cannot be equal to 0, has two unequal roots ...

College Algebra--Still Confused - I have a few problems I need help with and ...

College Algebra - I have a few problems I need help with and also do have ...

Precalculus - "Show that x^6 - 7x^3 - 8 = 0 has a quadratic form. Then find the ...

College math - Which statement describes the quadratic equation 6x^2-4x+1=0,...

Math - How to factor x^3 - 3x^2 + 4 =0 Use D'Alembert's Rational Roots Theorem. ...

Math - Roots Ok, what about roots? Roots of polynomials? Square roots? Cube ...

maths2 - Use the discriminant to determine the number of real roots the equation...

mathematics - Use the discriminant to determine the number of real roots the ...