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Adv algebra

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The equation x^2+px+q=0, q cannot be equal to 0, has two unequal roots such that the squares of the roots are the same as the two roots. Calculate the product pq.

  • Adv algebra - ,

    there is only one number which satisfies "the square of itself is equal to itself": it is 1. (0 is also the other but it is stated that q cannot be equal to 0)
    therefore,
    (x-1)(x-1) = x^2 + 2x + 1
    p = 2
    q = 1

    hope this helps~ :)

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