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December 17, 2014

December 17, 2014

Posted by **Ricky** on Saturday, October 22, 2011 at 11:49pm.

- Adv algebra -
**Jai**, Sunday, October 23, 2011 at 2:20amthere is only one number which satisfies "the square of itself is equal to itself": it is 1. (0 is also the other but it is stated that q cannot be equal to 0)

therefore,

(x-1)(x-1) = x^2 + 2x + 1

p = 2

q = 1

hope this helps~ :)

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