Post a New Question

Adv algebra

posted by .

The equation x^2+px+q=0, q cannot be equal to 0, has two unequal roots such that the squares of the roots are the same as the two roots. Calculate the product pq.

  • Adv algebra -

    there is only one number which satisfies "the square of itself is equal to itself": it is 1. (0 is also the other but it is stated that q cannot be equal to 0)
    (x-1)(x-1) = x^2 + 2x + 1
    p = 2
    q = 1

    hope this helps~ :)

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question