Posted by Mishaka on Saturday, October 22, 2011 at 8:32pm.
At x=0, a*cos(0)+b = 1 = 3x^2-2x+1
=> a+b= 1 = 3(0)-2(0)+1
At x=π/3,
a*cos(π/3) + b = 1 = 4sin^2(π/3)
=> (a/2) + b = 3/2 = 2*3/4
But you don't need to solve for a and b if only a+b is required. (see second line).
Related Questions
Calculus (Continuity) - If the following function is continuous, what is the ...
Calculus - consider k(t)=(e^t)/(e^t-7) on[-7,7] Is this function continuous on ...
Calculus - I don't know what to write for question b and c. 1 a)Determine ...
Calculus - consider k(t)=(e^t)/(e^t-7) on[-7,7] Is this function continuous on ...
Calculus - COnsider g(x)=(8)/(x-6) on (6,13) (a) Is this function continuous on ...
Calculus - COnsider g(x)=(8)/(x-6) on (6,13) (a) Is this function continuous on ...
Calculus - COnsider g(x)=(8)/(x-6) on (6,13) (a) Is this function continuous on ...
Calculus - A function f(x) is said to have a removable discontinuity at x=a if: ...
Calculus - A function f(x) is said to have a removable discontinuity at x=a if: ...
Calculus - consider k(t)=(e^t)/(e^t-7) on[-7,7] Is this function continuous on ...
For Further Reading