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December 18, 2014

December 18, 2014

Posted by **Steph** on Saturday, October 22, 2011 at 7:45pm.

A) 0.0026

B) 0.4987

C) 3.00

D) 0.9974

- Statistics -
**PsyDAG**, Sunday, October 23, 2011 at 2:41pmZ = (score-mean)/SEm

SEm = SD/√n

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportions related to the Z scores.

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