Posted by Mishaka on Saturday, October 22, 2011 at 7:30pm.
I assume you do not have a typo and it is not x^2-2ax+a^2
That said, the function is undefined and also discontinuous as x = a is approached. However since a separate f(a) is given the function exists at x = a so I agree D
No, its not a typo, it is supposed to be x^2 - 2a + a^2. Thank you for the reassurance, I figured that this was the most logical choice!
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