Posted by Johnna on Saturday, October 22, 2011 at 6:40pm.
Wb = mg = 3kg * 9.8N/kg = 29.4N.
Fb = (29.4N,33deg).
Fp = 29.4sin33 = 16.o1N. = Force parallel to incline.
Fv = 29.4cos33 = 24.66N. = Force perpendicular to incline.
d = Vo*t + 0.5at^2 = 2.0m,
0*1.75 + 4.9a*(1.75)^2 = 2,
15a = 2,
a = 0.133m/s^2.
Fn = Fp - Ff = ma,
16.01 - Ff = 3 * 0.133,
16.01- Ff = 0.40,
Ff = 16.01 - 0.40 = 15.61N.
u = Ff / Fv = 15.61 / 24.66 = 0.633 =
coefficient of kinetic friction.
Related Questions
Physics - A 3.00-kg block starts from rest at the top of a 33.5° incline and...
physics - A 3.00-kg block starts from rest at the top of a 27.5° incline and...
physics - A 3.00 kg block starts from rest at the top of a 36.0'> ...
physics - A 3.00 kg block starts from rest at the top of a 36.0'> ...
physics - A 3.00 kg block starts from rest at the top of a 36.0'> ...
physics - A block of mass m = 2.00 kg is released from rest at h = 0.400 m from...
physics - A block of mass 12.0 kg slides from rest down a frictionless 35.0°...
college physics - A block of mass 12.0 kg slides from rest down a frictionless ...
physics - A 3.00 kg block starts from rest at the top of a 30° incline and ...
physics - A 20. kg block is placed at the top of a 10. meter-long inclined plane...
For Further Reading