Posted by Nick on .
The highest barrier that a projectile can clear is 15.8 m, when the projectile is launched at an angle of 13.4° above the horizontal. What is the projectile's launch speed?
"vertical" kinetic energy = max potential energy change.
(Horizontal kinetic energy does not change)
(Vo sin13.4)^2/2 = 2g H
Solve for Vo.