An Olympic basketball player shoots towards a basket that is 5.64 m horizontally from her and 3.05 m above the floor. The ball leaves her hand 1.71 m above the floor at an angle of 41.0o above the horizontal. What initial speed should she give the ball so that it reaches the basket and hopefully scores?

Dh=Vo^2*sin(2A) / g = 5.64m = Hor.Dist.

Vo^2*sin82 / 9.8 = 5.64,
Multiply both sides by 9.8:
Vo^2*sin82 = 55.27,
V0^2 = 55.27 / sin82 = 55.82,
Vo = 7.47m/s.