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as a hot air balloon rises vertically, its angle of elevation from point P on level ground 110 kilometers from th epoint Q directly underneath the balloon changes from 15 degree 5' to 31 degree 45'.
Approximately how far does the balloon rise during this period?
a. 38.4 km
b. 97.7 km
c.106.5 km
d. 86.5 km
e. 199.7 km
i need help solving this

  • trig - ,

    If the balloon rises from height h to height H,

    h/110 = tan(15°5')
    H/110 = tan(31°45')

    Distance risen = H-h

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