Posted by **Yousef** on Saturday, October 22, 2011 at 7:31am.

Find the first derivative for the following functions

1) f(x) = sin(cos^2x) cos(sin^3x)

2) f(x) = ( tan 2x - tan x ) / ( 1 + tan x tan 2x )

3) f(x) = sin { tan ( sqrt x^3 + 6 ) }

4) f(x) = {sec^2(100x) - tan^2(100x)} / x

- Maths Calculus Derivatives -
**Steve**, Saturday, October 22, 2011 at 11:49am
Just gonna dump some problems on us?

The solution to your previous posting should help some.

Hints:

1) use product rule, chain rule

2) use quotient rule, chain rule

3) use chain rule, chain rule, chain rule

4) use quotient rule, chain rule

## Answer this Question

## Related Questions

Trig - Given: cos u = 3/5; 0 < u < pi/2 cos v = 5/13; 3pi/2 < v < ...

precalculus - For each of the following determine whether or not it is an ...

Trigonometry - Please review and tell me if i did something wrong. Find the ...

Trigonometry - 1.Solve tan^2x + tan x – 1 = 0 for the principal value(s) to two ...

Trigonometry desperate help, clueless girl here - 2. solve cos 2x-3sin x cos 2x...

math - Use the exact values of the sin, cos and tan of pi/3 and pi/6, and the ...

Mathematics - Trigonometric Identities - Let y represent theta Prove: 1 + 1/tan^...

math - Use the exact values of the sin, cos and tan of pi/3 and pi/6, and the ...

Maths- complex numbers - Find tan(3 theta) in terms of tan theta Use the formula...

Trig Identities - Proving identities: 1) 1+ 1/tan^2x = 1/sin^2x 2) 2sin^2 x-1 = ...