Friday

April 18, 2014

April 18, 2014

Posted by **Louis** on Saturday, October 22, 2011 at 3:43am.

- Math -
**Reiny**, Saturday, October 22, 2011 at 9:06amtime needed by 2nd faucet alone --- t hrs

rate for 2nd faucet alone = 1/t

time needed by 1st faucet alone --- t+2 hrs

rate of 1st faucet along = 1/(t+2)

combined rate = 1/t + 1/(t+2)

= (t+2 + t)/(t(t+2) = (2t+2)/(t(t+2))

then 1/[ 2t+2)/(t(t+2)) ] = 4/3

t(t+2)/(2t+2) = 4/3

3t^2 + 6t = 8t + 8

3t^2 - 2t - 8 = 0

(t-2)(3t+4) = 0

t = 2 or t = a negative time

the 2nd faucet would take 2 hours alone

the 1st facucet would take 4 hours alone

- Math -
**Anonymous**, Monday, August 20, 2012 at 10:32am1 + 1

**Related Questions**

physics - A fire hose can fill a certain tank with water during 1 hour. A 2nd ...

college algebra - A paint-mixing machine has 2 inlet pipes. One takes 1 hour ...

Math - If it takes 16 faucets 10 hours to fill 8 tubs, how long will it take 12 ...

science - a large fiberglass tank was placed in a pit, before pipes could be ...

Math - Two taps named tap A and B are used to fill a tank. Tap A on its own ...

akgebra - One pipe can fill a tank in 20 minutes, while another takes 30 minutes...

math - Filling a tank. Two pipes are connected to the same tank. Working ...

math - It takes 1 and 3/4 hours to fill a new underground gasoline storage tank...

Algebra I - Pump A, working alone, can fill a tank in 3 hours, and pump B can ...

college algebra - water from a tank is being used for irrigation while the tank ...