Posted by **Anonymous** on Friday, October 21, 2011 at 9:18pm.

The only force acting on a 2.3 kg body as it moves along the positive x axis has an x component Fx = - 6x N, where x is in meters. The velocity of the body at x = 3.0 m is 8.0 m/s.

At what positive value of x will the body have a velocity of 5.0 m/s?

I'm not sure how to approach this. So far I have written down KE=(1/2)mv^2,

but I haven't the slightest idea where to go from here...

- PHYSICS -
**drwls**, Saturday, October 22, 2011 at 2:18am
What you have is a spring-mass system, with spring constant 6.0 N/m.

Total energy, which is constant, is

(1/2)kX^2 + (1/2)MV^2

= 3*9 + 1.15*64 = 100.6 J

(using data at the X = 3.0 m location)

Solve for X when V = 5 m/s

100.6 = 3*X*2 + 1.15*25

X^2 = 23.95 m^2

X = 4.9 m

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