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September 30, 2014

September 30, 2014

Posted by **Student 315** on Friday, October 21, 2011 at 8:46pm.

a. Solve the equation r^-2 = wC^-1 for r. Solve the equation for C. Solve the equation for w.

b. Suppose that an object is 350 pounds when it is at sea level. Find the value of C that makes the equation true. (Sea level is approximately 4,000 miles from the center of the earth.)

c. Use the value of C you found in the previous question to determine how much the object would weigh

i. 1,100 feet below sea level (for example, near the bottom of the ocean)

ii. 21,500 feet above sea level (for example, on the top of a high mountain)

- Math -
**Reiny**, Friday, October 21, 2011 at 9:20pmr^-2 = wC^-1

or

1/r^2 = w/C

C = wr^2 or w = C/r^2

b) if w=350 and r = 4000(5280)

C = 350(4000*5280)^2

c) i) if r = 40005280) -1100 = 21118900

w = C/r^2 = 350.036

ii, use r = 4000(5280) + 21500

to get w = 349.29

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