Posted by Sam on Friday, October 21, 2011 at 6:36pm.
The problem may well be the ambiguity in the molarity of glacial acetic acid. The molarity depends upon the density and percent composition.
mLacid x M acid = 155 x 0.25
IF we use 100% for the glacial acetic acid (I see 98-100% on the bottles) and density of 1.049 g/mL, then the calculated molarity of glacial acetic acid is 17.4M.)
So you need (155 x 0.25/17.4) = 2.227 mL which you would round to 2.23 mL.
Then 109 drops x (2.23 mL/2.00 mL) = ?
drops. You can adjust the numbers depending upon the molarity of the glacial acetic acid you are using.
Thank you so much!
Related Questions
chemistry - A student found that there are 115 drops of glacial acetic acid in 2...
chemistry - A student found that there are 93 drops of glacial acetic acid in 2....
Chemistry - Pure acetic acid, known as glacial acetic acid, is a liquid with a ...
chemistry - If 15.0 mL of glacial acetic acid (pure HC2H3O2) is diluted to 1.50 ...
College Chem. - If 20.0 mL of glacial acetic acid (pure HC2H3O2) is diluted to 1...
Chemistry - I have no idea where to even start with this problem on my pre-lab! ...
Chemistry - If 20ml of glacial acetic acid (pure HC2H3O2) is diluted to 1.5L ...
chemistry - How many grams of glacial acetic acid should be used to make 250 mL ...
chemistry - How many grams of glacial acetic acid should be used to make 250 mL ...
chemistry - You want to make an acetic acid/acetate buffer, pH 3.8, with a ...
For Further Reading
