Posted by Riley on Friday, October 21, 2011 at 9:31am.
find the surface area of the water in the tank at 3 meters from the bottom (pointy end), pi r^2 (in CENTIMETERS squared)
then
dh (pi r^2 = dV
pi r^2 (dh/dt ) = dV/dt
so
dh/dt = (1/pir^2) dV/dt
23 = (1/pir^2)(flow rate in - 1100)
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