Posted by mymi on Friday, October 21, 2011 at 12:04am.
Given: D = 1.1m., V0 = 30m/s, 49rev.
C = pi*D = 3.14 * 1.1 = 3.46m. = Circumference of tirs.
a. Vo = 30m/s * 6.28rad/3.46m = 54.5rad/s.
b. d = 49rev * 3.46m/rev = 169.3m =
stopping dist.
a = (Vf^2 - Vo^2) / 2d,
a = (0 - (30)^2) / 338.6 = -2.66m/s^2 =
Linear acceleration.
a = -2.66m/s^2 * 6.28rad/3.46m =
-4.82rad/s^2. = Angular acceleration.
c. d = 49rev * 3.46m/rev = 169.3m.
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