Post a New Question

Physics.

posted by .

A monster truck has tires with a diameter of 1.10 m and is traveling at 30.0 m/s. After the brakes are applied, the truck slows uniformly and is brought to rest after the tires rotate through 49.0 turns.
(a) What is the initial angular speed of the tires?


(b) What is the angular acceleration of the tires? (Enter the magnitude only.)


(c) What distance does the truck travel before coming to rest?

  • Physics. -

    Given: D = 1.1m., V0 = 30m/s, 49rev.

    C = pi*D = 3.14 * 1.1 = 3.46m. = Circumference of tirs.

    a. Vo = 30m/s * 6.28rad/3.46m = 54.5rad/s.

    b. d = 49rev * 3.46m/rev = 169.3m =
    stopping dist.
    a = (Vf^2 - Vo^2) / 2d,
    a = (0 - (30)^2) / 338.6 = -2.66m/s^2 =
    Linear acceleration.

    a = -2.66m/s^2 * 6.28rad/3.46m =
    -4.82rad/s^2. = Angular acceleration.



    c. d = 49rev * 3.46m/rev = 169.3m.

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question