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January 30, 2015

January 30, 2015

Posted by **casey** on Thursday, October 20, 2011 at 10:53pm.

- chemistry -
**Jai**, Thursday, October 20, 2011 at 11:04pmrecall that the amount of heat absorbed or released is given by:

Q = mc(T2-T1)

where

m = mass (in g)

c = specific heat capacity (in J/g-K)

T = temperature (in C or K)

*note: Q = (+) when heat is absorbed and (-) when heat is released

to get the final temp, we note that Q,released = Q,absorbed. therefore:

Q,released = Q,absorbed

-m1*c1*(T2-T,r1) = m2*c2*(T2-T,a1)

we're solving for c1, which is the specific heat capacity of gold.

assuming that the density of water is 1g/mL, the mass of water (for a volume equal to 15 mL) is equal to 15 g. substituting,

-10*c1*(26.34-90) = 15*4.184*(26.34-25)

636.6*c1 = 84.0984

c1 = 0.1321 J/g-K

hope this helps~ :)

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