Posted by casey on Thursday, October 20, 2011 at 10:53pm.
A 10.0 grams piece of gold 90.0 Celsius was stirred into 15.0ml of water at an initial temperature of 25.0 degrees Celsius. The final temperature of the water was 26.34 degrees celsius. Calculate the specific heat of gold. The specific heat of water is 4.184 J/g degrees celsius

chemistry  Jai, Thursday, October 20, 2011 at 11:04pm
recall that the amount of heat absorbed or released is given by:
Q = mc(T2T1)
where
m = mass (in g)
c = specific heat capacity (in J/gK)
T = temperature (in C or K)
*note: Q = (+) when heat is absorbed and () when heat is released
to get the final temp, we note that Q,released = Q,absorbed. therefore:
Q,released = Q,absorbed
m1*c1*(T2T,r1) = m2*c2*(T2T,a1)
we're solving for c1, which is the specific heat capacity of gold.
assuming that the density of water is 1g/mL, the mass of water (for a volume equal to 15 mL) is equal to 15 g. substituting,
10*c1*(26.3490) = 15*4.184*(26.3425)
636.6*c1 = 84.0984
c1 = 0.1321 J/gK
hope this helps~ :)
Answer This Question
Related Questions
 Physics 20  1. How much heat energy is required to change 500 grams of water at...
 Science  A piece of unknown metal with a mass of 68.6 grams is heated to an ...
 Physics  Please Help! I am having difficulties grasping these concepts. Explain...
 Chemistry  Calculate the joules of energy involved when 11 grams of water at 10...
 Chem 103  a piece of gold is heated to 100 degrees celsius. A piece of copper ...
 Chemistry  A 125g piece of metal is heated to 288 degrees celsius and dropped ...
 Physics  The water from two buckets is mixed together. One bucket contains 5kg ...
 Chemistry  A 50g sample of metal was heated to 100 degrees Celsius and then ...
 western michigan university  A 30 gram metal at 100 degrees Celsius was dropped...
 chemistry  if 27 grams of ice at 0 degrees celsius is added to 123 grams of ...
More Related Questions