Posted by Nia on Thursday, October 20, 2011 at 10:03pm.
Your Ka is right but I would have written H3O^+ on the right instead of H^+.
Your Kb shows HSO3^- donating a proton to H2O; therefore, that is an acid reaction. You want it accepting a proton.
HSO3^- + H2O ==> H2SO3 + OH^-
Kb = (H2SO3)/(H^+)(HSO3^-)
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