Posted by **marko** on Thursday, October 20, 2011 at 9:31pm.

six familys split the cost of a family reunion. each family also spends $65 for a hotel room. Each familys share of the cost of the party plus the cost of the hotel room totlas $160. write and solve and equation to find the cost of the reunion.

i don't know how to do this without knowing how many days they are staying at the hotel? or can i still do this problem?

im stuck.

- algeBRA WORD PROBLEM -
**Ms. Sue**, Thursday, October 20, 2011 at 9:36pm
I think you have to assume that each family stays at the motel just one night.

- algeBRA WORD PROBLEM -
**marko**, Thursday, October 20, 2011 at 9:39pm
so 65.00 + r/6 + $160.00

- algeBRA WORD PROBLEM -
**Ms. Sue**, Thursday, October 20, 2011 at 9:42pm
You haven't written an equation.

- algeBRA WORD PROBLEM -
**marko**, Thursday, October 20, 2011 at 9:44pm
65.00 + r/6 + $160.00

- algeBRA WORD PROBLEM -
**Ms. Sue**, Thursday, October 20, 2011 at 9:54pm
An equation needs an equal sign.

- algeBRA WORD PROBLEM -
**marko**, Thursday, October 20, 2011 at 9:57pm
65.00 + r/6 = $160.00

- algeBRA WORD PROBLEM -
**Ms. Sue**, Thursday, October 20, 2011 at 10:03pm
That answer doesn't make any sense.

In your equation r = 15.83

You need to find the total cost of the reunion party.

- algeBRA WORD PROBLEM -
**marko**, Thursday, October 20, 2011 at 10:05pm
$160.00 /6 = x

- algeBRA WORD PROBLEM -
**Ms. Sue**, Thursday, October 20, 2011 at 10:14pm
Nope!

Each family pays $160. Of that amount, $65 is for the hotel room.

6(160 - 65) = t

- algeBRA WORD PROBLEM -
**marko**, Thursday, October 20, 2011 at 10:18pm
t = 570.00

- algeBRA WORD PROBLEM -
**Ms. Sue**, Thursday, October 20, 2011 at 10:25pm
Right. Doesn't that make sense?

- algeBRA WORD PROBLEM -
**mackenzie**, Wednesday, November 18, 2015 at 2:46pm
6(160-65)=p

160-65= 95

6(95)=p

p= $570

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