Posted by **Ricky** on Thursday, October 20, 2011 at 9:30pm.

The equation x^2+px+q=0, q cannot be equal to 0, has two unequal roots such that the squares of the roots are the same as the two roots. Calculate the product pq.

I think the obvious root would be one but the second roots i just can't figure out!

## Answer This Question

## Related Questions

- Adv algebra - The equation x^2+px+q=0, q cannot be equal to 0, has two unequal ...
- Math - The equation x^2+px+q=0, q cannot be equal to 0, has two unequal roots ...
- College Algebra--Still Confused - I have a few problems I need help with and ...
- College Algebra - I have a few problems I need help with and also do have ...
- Pre-Calc/Trig... - Helpp needed, this is sort of confusing me. Describe the ...
- Algebra - Given the roots, 1/2 and 4, find: (A) The quadratic equation 2x^2-9x+4...
- Precalculus - "Show that x^6 - 7x^3 - 8 = 0 has a quadratic form. Then find the ...
- Math - How to factor x^3 - 3x^2 + 4 =0 Use D'Alembert's Rational Roots Theorem. ...
- College math - Which statement describes the quadratic equation 6x^2-4x+1=0,...
- Math - Roots Ok, what about roots? Roots of polynomials? Square roots? Cube ...

More Related Questions