Post a New Question


posted by .

Given that Kw for water is 2.4× 10–14 at 37 °C, compute the pH of a neutral aqueous solution at 37 °C, which is the normal human body temperature.

  • Chemistry -

    kw=conccH+ * concOH- where they are equal.
    x=sqrt kw=sqrt(2.4E-14)=1.55 E-7

    pH=-log (1.55E-7)=6.81

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question