Chemistry
posted by John .
Given that Kw for water is 2.4× 10–14 at 37 °C, compute the pH of a neutral aqueous solution at 37 °C, which is the normal human body temperature.

kw=conccH+ * concOH where they are equal.
kw=x^2
x=sqrt kw=sqrt(2.4E14)=1.55 E7
pH=log (1.55E7)=6.81