Posted by Cole on Thursday, October 20, 2011 at 7:06pm.
Y = -0.005x^2 + x + 3
A. h = Xv = -b / 2a = -1 / -0.01 = 100 X = 100 = Eq of axis of symmetry.
B. The max ht = Y-coordinate of vertex.
In the given Eq, substitute 100 for X
and get: Yv = K = 53 = max ht.
V(h,k) = V(100,53).
C. Y = -0.005x^2 + x + 3 = 3,
-0.005x^2 + x = 3-3 = 0,
x(-0.005x + 1) = 0,
X = 0,
-0.005x + 1 = 0,
0.005x = 1,
X = 200 = Hor. distance traveled.
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